Difference between revisions of "Concepts in Action: Relationship between T1 and T2"
From wikisori
					
										
					
					 (New page: === Age  ===  <br>   === Materials  ===  <br>   === Preparation  ===  <br>   === Presentation  ===  <br>   === Control Of Error  ===  <br>   === Points Of Interest  ===  <br>   === Purpose...)  | 
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=== Age  ===  | === Age  ===  | ||
| − | <br>    | + | 6-9.<br>  | 
=== Materials  ===  | === Materials  ===  | ||
| − | <br>    | + | <br>  | 
=== Preparation  ===  | === Preparation  ===  | ||
| − | <br>    | + | <br>  | 
=== Presentation  ===  | === Presentation  ===  | ||
| − | <br>    | + | #With the pieces of the small hexagonal box, form various figure: hexagon, trapezoid, rhombus, and equilateral triangle and hexagon.   | 
| + | #Superimpose the grey hexagon on the red and yellow hexagon to demonstrate congruency.  | ||
| + | #Recall the value relationships already established.   | ||
| + | #Since the equilateral triangle is equal to 1/2 the red hexagon, then it is also equal to 1/2 of the grey hexagon - or a trapezoid.  | ||
| + | #Bring from the triangular box the grey unit triangle (T1) and the four small red equilateral triangles (T3).  | ||
| + | #We know that the yellow triangle T2 is equivalent to the trapezoid which is 1/2 of the grey hexagon.  | ||
| + | #One of the triangles of the trapezoid is congruent to one of the small red equilateral triangles (T3).   | ||
| + | #Superimpose them.   | ||
| + | #Thus, one red triangle is 1/3 of the trapezoid.  | ||
| + | #The red triangle as we know is 1/4 of the large grey unit triangle (T1).  | ||
| + | #Four of these red triangles are equivalent to the grey unit triangle.  | ||
| + | #Because the yellow triangle (T2) is made up of three of the small red triangles (T3), then we can say that the yellow triangle (T2) is made up of 3/4 (T3) of the grey unit triangle (T2 = 3/4 T1).<br>  | ||
=== Control Of Error  ===  | === Control Of Error  ===  | ||
| − | <br>    | + | <br>  | 
=== Points Of Interest  ===  | === Points Of Interest  ===  | ||
| − | <br>    | + | <br>  | 
=== Purpose  ===  | === Purpose  ===  | ||
| − | <br>    | + | <br>  | 
=== Variation  ===  | === Variation  ===  | ||
| − | <br>    | + | <br>  | 
=== Links  ===  | === Links  ===  | ||
| − | <br>    | + | <br>  | 
=== Handouts/Attachments  ===  | === Handouts/Attachments  ===  | ||
| − | <br>    | + | <br>  | 
| − | [[Category:Mathematics]]  | + | [[Category:Mathematics]] [[Category:Mathematics_6-9]]  | 
Latest revision as of 05:23, 11 August 2009
Contents
Age
6-9.
Materials
Preparation
Presentation
- With the pieces of the small hexagonal box, form various figure: hexagon, trapezoid, rhombus, and equilateral triangle and hexagon.
 - Superimpose the grey hexagon on the red and yellow hexagon to demonstrate congruency.
 - Recall the value relationships already established.
 - Since the equilateral triangle is equal to 1/2 the red hexagon, then it is also equal to 1/2 of the grey hexagon - or a trapezoid.
 - Bring from the triangular box the grey unit triangle (T1) and the four small red equilateral triangles (T3).
 - We know that the yellow triangle T2 is equivalent to the trapezoid which is 1/2 of the grey hexagon.
 - One of the triangles of the trapezoid is congruent to one of the small red equilateral triangles (T3).
 - Superimpose them.
 - Thus, one red triangle is 1/3 of the trapezoid.
 - The red triangle as we know is 1/4 of the large grey unit triangle (T1).
 - Four of these red triangles are equivalent to the grey unit triangle.
 - Because the yellow triangle (T2) is made up of three of the small red triangles (T3), then we can say that the yellow triangle (T2) is made up of 3/4 (T3) of the grey unit triangle (T2 = 3/4 T1).
 
Control Of Error
Points Of Interest
Purpose
Variation
Links
Handouts/Attachments
