Difference between revisions of "Concepts in Action: Relationship between T1 and T2"
From wikisori
(New page: === Age === <br> === Materials === <br> === Preparation === <br> === Presentation === <br> === Control Of Error === <br> === Points Of Interest === <br> === Purpose...) |
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Line 1: | Line 1: | ||
=== Age === | === Age === | ||
− | <br> | + | 6-9.<br> |
=== Materials === | === Materials === | ||
− | <br> | + | <br> |
=== Preparation === | === Preparation === | ||
− | <br> | + | <br> |
=== Presentation === | === Presentation === | ||
− | <br> | + | #With the pieces of the small hexagonal box, form various figure: hexagon, trapezoid, rhombus, and equilateral triangle and hexagon. |
+ | #Superimpose the grey hexagon on the red and yellow hexagon to demonstrate congruency. | ||
+ | #Recall the value relationships already established. | ||
+ | #Since the equilateral triangle is equal to 1/2 the red hexagon, then it is also equal to 1/2 of the grey hexagon - or a trapezoid. | ||
+ | #Bring from the triangular box the grey unit triangle (T1) and the four small red equilateral triangles (T3). | ||
+ | #We know that the yellow triangle T2 is equivalent to the trapezoid which is 1/2 of the grey hexagon. | ||
+ | #One of the triangles of the trapezoid is congruent to one of the small red equilateral triangles (T3). | ||
+ | #Superimpose them. | ||
+ | #Thus, one red triangle is 1/3 of the trapezoid. | ||
+ | #The red triangle as we know is 1/4 of the large grey unit triangle (T1). | ||
+ | #Four of these red triangles are equivalent to the grey unit triangle. | ||
+ | #Because the yellow triangle (T2) is made up of three of the small red triangles (T3), then we can say that the yellow triangle (T2) is made up of 3/4 (T3) of the grey unit triangle (T2 = 3/4 T1).<br> | ||
=== Control Of Error === | === Control Of Error === | ||
− | <br> | + | <br> |
=== Points Of Interest === | === Points Of Interest === | ||
− | <br> | + | <br> |
=== Purpose === | === Purpose === | ||
− | <br> | + | <br> |
=== Variation === | === Variation === | ||
− | <br> | + | <br> |
=== Links === | === Links === | ||
− | <br> | + | <br> |
=== Handouts/Attachments === | === Handouts/Attachments === | ||
− | <br> | + | <br> |
− | [[Category:Mathematics]] | + | [[Category:Mathematics]] [[Category:Mathematics_6-9]] |
Latest revision as of 05:23, 11 August 2009
Contents
Age
6-9.
Materials
Preparation
Presentation
- With the pieces of the small hexagonal box, form various figure: hexagon, trapezoid, rhombus, and equilateral triangle and hexagon.
- Superimpose the grey hexagon on the red and yellow hexagon to demonstrate congruency.
- Recall the value relationships already established.
- Since the equilateral triangle is equal to 1/2 the red hexagon, then it is also equal to 1/2 of the grey hexagon - or a trapezoid.
- Bring from the triangular box the grey unit triangle (T1) and the four small red equilateral triangles (T3).
- We know that the yellow triangle T2 is equivalent to the trapezoid which is 1/2 of the grey hexagon.
- One of the triangles of the trapezoid is congruent to one of the small red equilateral triangles (T3).
- Superimpose them.
- Thus, one red triangle is 1/3 of the trapezoid.
- The red triangle as we know is 1/4 of the large grey unit triangle (T1).
- Four of these red triangles are equivalent to the grey unit triangle.
- Because the yellow triangle (T2) is made up of three of the small red triangles (T3), then we can say that the yellow triangle (T2) is made up of 3/4 (T3) of the grey unit triangle (T2 = 3/4 T1).
Control Of Error
Points Of Interest
Purpose
Variation
Links
Handouts/Attachments